Question

A tennis ball is dropped from 1.98m above the ground. It rebounds to a height of 0.873 m. With what velocity does it hit the ground. The acceleration of gravity is 9.8 m/s^2. (Let down be negative.)

Answer 1

the velocity at which it hits the ground is 4.8497

Step-by-step explanation:

A tennis ball is dropped from 1.20 m above the ground.

According to kinematic equation of motion,

Where v = final velocity of the ball

u = initial velocity of the ball = 0

a = acceleration due to gravity = 9.8

s = distance travelled by the ball = 1.2 meter

Thus,

= 0 + 2 × 9.8 × 1.2

= 23.52

v = 4.8497