Question

4. Calculate the number of carbon (C) atoms present in the 25 mL of sugar.

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Answer 1

Answer:
`8.38* 10^(23)atoms` of carbon

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

mass of sugar=
`density* volume=1.59g/ml* 25ml=39.75g`

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(39.75g)/(342.3g/mol)=0.116moles`

1 mole of sugar
`C_(12)H_(22)O_(11))` contains =
`12* 6.023* 10^(23)=72.28* 10^(23)atoms` of carbon

0.116 mole of sugar
`C_(12)H_(22)O_(11))` contains =
`(72.28* 10^(23))/(1)* 0.116=8.38* 10^(23)atoms` of carbon