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Find two numbers whose sum is 0 and whose difference is 8

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Answer:

Explanation:

Let's call the two numbers we're looking for x and y. We know that their sum is 0, so x + y = 0. We also know that their difference is 8, so x - y = 8.

We can solve this system of equations by adding the two equations together. This gives us:

x + y = 0

x - y = 8

-------

2x = 8

Solving for x, we get x = 4. We can then substitute this value of x into either of the original equations to find y. Using x + y = 0, we get:

4 + y = 0

y = -4

Therefore, the two numbers we're looking for are **4** and **-4**. These two numbers have a sum of **0** and a difference of **8**.

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