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Find the value of k, for which x=2 is a solution of the equation kx²+2x−3=0.

1 Answer

2 votes

Answer:

k = -1/4

Explanation:

I think they're just saying to put '2' in every place where you see an 'x' and then solve for k:


kx^(2) + 2x - 3 = 0


k(2^(2)) + 2(2) - 3 = 0

4k + 4 - 3 = 0

4k + 1 = 0

4k = -1

k = -1/4

Let's check if it works by putting in x = 2 and k = -1/4:


-1/4(2^(2)) + 2(2) -3 = 0

-1 + 4 - 3 = 0

0 = 0 So yes, the answer checks out.

User Stephendwolff
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