Question

Find the value of k, for which x=2 is a solution of the equation kx²+2x−3=0.

Answer 1

k = -1/4

Explanation:

I think they're just saying to put '2' in every place where you see an 'x' and then solve for k:

`kx^(2) + 2x - 3 = 0`

`k(2^(2)) + 2(2) - 3 = 0`

4k + 4 - 3 = 0

4k + 1 = 0

4k = -1

k = -1/4

Let's check if it works by putting in x = 2 and k = -1/4:

`-1/4(2^(2)) + 2(2) -3 = 0`

-1 + 4 - 3 = 0

0 = 0 So yes, the answer checks out.