Question

Non-acetone is ethyl acetate, and it has a density of 0.9021 g/cm3. What is the volume in mL of 484.31 g of ethyl acetate

Answer 1

To find the volume of 484.31 grams of ethyl acetate, you can use the formula:

Volume (in mL) = Mass (in grams) / Density (in g/cm³)

Given:

Mass = 484.31 g

Density = 0.9021 g/cm³

Now, plug in these values into the formula:

Volume = 484.31 g / 0.9021 g/cm³

Volume ≈ 536.74 cm³

Since 1 cm³ is equal to 1 mL, the volume in mL is also 536.74 mL.

So, the volume of 484.31 grams of ethyl acetate is approximately 536.74 mL.