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Mathematical Reasoning 1. Consider LET + LEE = ALL where every letter represents a unique digit from 0 to 9, find out (A+L+L) if E=5. a) L b) LE c) E d) A e) TL

User Rsc
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Final answer:

In the cryptarithm LET + LEE = ALL, assuming E=5, we calculate A=1 and L=5. Therefore, A + L + L = 1 + 5 + 5 = 11, which doesn't match any of the provided options, suggesting an error in the question.

Step-by-step explanation:

This problem is a type of cryptarithm, or a number-based puzzle. Knowing that E represents 5, let's solve it step by step. From the rightmost column, we recognize that T + E should end in L. If T=0, this gives us L=5, but we already know E=5, so it's impossible, as each letter represents a unique digit. So it means T+5 ends in L and T should be 5 less than L or T+5+10=L if L

Moving to the first column, we have L + L (plus possibly that carried 1) equals to A. As L must be >=5, the only way for the sum of L + L + 1 to not exceed the digit limit (9) is if L = 5, which means 5 + 5 + 1 = 11. A = 1, 1 over 10 is discarded. So A = 1 and L = 5.

In the equation A + L + L = 1 + 5 + 5 = 11, so the answer to the question 'what is (A+L+L)' is 11, which is not included in the options given. Therefore, the question appears to contain a mistake.

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User Russell Shingleton
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