Question

Greg's favorite snack is apples and cheese. Last week, he bought 2

1/4
pounds of apples and $5.73 worth of cheese. This week, he bought 1
4/5
pounds of apples and $6.54 worth of cheese. Greg realized that he spent the exact same amount each week.
What is the price of one pound of apples?

Answer 1

Answer:

$1.80

Explanation:

Let "a" be the price of one pound of apples in dollars.

For the first week:

Greg bought 2 1/4 pounds of apples, which can be written as 2.25 pounds.

He spent $5.73 on cheese.

Therefore, we can express the total amount he spent in the first week as 2.25a + 5.73.

For the second week:

Greg bought 1 4/5 pounds of apples, which can be written as 1.8 pounds.

He spent $6.54 on cheese.

Therefore, we can express the total amount he spent in the second week as 1.8a + 6.54.

Since Greg spent the exact same amount each week, we can set the expressions equal to each other and solve for a:

Therefore, the price of one pound of apples is $1.80.

Explanation:

Answer 2

$1.80

Explanation:

Let "a" be the price of one pound of apples in dollars.

For the first week:

• Greg bought 2 1/4 pounds of apples, which can be written as 2.25 pounds.
• He spent $5.73 on cheese.

Therefore, we can express the total amount he spent in the first week as 2.25a + 5.73.

For the second week:

• Greg bought 1 4/5 pounds of apples, which can be written as 1.8 pounds.
• He spent $6.54 on cheese.

Therefore, we can express the total amount he spent in the second week as 1.8a + 6.54.

Since Greg spent the exact same amount each week, we can set the expressions equal to each other and solve for a:

`\begin{aligned}\sf 2.25a + 5.73 &= \sf 1.8a + 6.54\\\sf 2.25a + 5.73 - 1.8a &= \sf 1.8a + 6.54 - 1.8a\\\sf 0.45a + 5.73 &= \sf 6.54\\\sf 0.45a + 5.73 - 5.73 &= \sf 6.54 - 5.73\\\sf 0.45a &= \sf 0.81\\\sf 0.45a / 0.45 &=\sf 0.81 / 0.45\\\sf a &= \sf 1.8\end{aligned}`

Therefore, the price of one pound of apples is $1.80.