Question

Suppose that on a linear temperature scale X, water boils at 53.5 X and freezes at 170 X. What is a temperature of 340 K on the X scale?

Answer 1

On the X scale, a temperature of 340 K would be approximately 78.52 X.

Define the temperature difference: We know the boiling point (53.5 X) and freezing point (170 X) on the X scale. So, the temperature difference between these points is 170 X - 53.5 X = 116.5 X.

Calculate the conversion factor: We also know that 340 K corresponds to the boiling point on the Kelvin scale (373 K). Since the X scale is linear, the temperature difference between these points on both scales should be proportional. Therefore, the conversion factor from Kelvin to X is (116.5 X) / (373 K - 340 K) = 4.33 K/X.

Convert the temperature: Finally, we can convert 340 K to the X scale using the conversion factor: 340 K * (4.33 K/X) ≈ 78.52 X.

Therefore, a temperature of 340 K on the Kelvin scale is equivalent to approximately 78.52 X on the X scale.