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A 30cm diameter wheel rotates with a constant angular acceleration of 2.00 rad/s2. It starts from rest at t = 0, and a chalk line drawn to a point, P, on the rim of the wheel makes an angle of 37.1° with the horizontal at this time. At t = 2.00 s, find (a) the angular speed of the wheel (b) the linear velocity and tangential acceleration of P

User Jma
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1 Answer

1 vote

Answer:

a) 4.00 rad/s

b) 0.6 m/s, 0.3 m/s²

Step-by-step explanation:

Given:

ω₀ = 0 rad/s

α = 2.00 rad/s²

t = 2.00 s

Find:

a) ω

b) v, a

a) ω = αt + ω₀

ω = (2.00 rad/s²) (2.00 s) + (0 rad/s)

ω = 4.00 rad/s

b) v = ωr

v = (4.00 rad/s) (0.15 m)

v = 0.6 m/s

a = αr

a = (2.00 rad/s²) (0.15 m)

a = 0.3 m/s²

User Liam M
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8.2k points