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If a/b=7/3 then find the value of ( aA³-bA³)/bA³

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Explanation:

To find the value of (a^3 - b^3) / b^3 given that a/b = 7/3, you can use the formula for the difference of cubes:

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

First, find the value of a - b using a/b = 7/3:

a/b = 7/3

Cross-multiply:

3a = 7b

Now, solve for a - b:

a - b = (3a - 7b)/3

Next, square the values of a and b:

a^2 = (a^2)

b^2 = (b^2)

Now, add ab to both sides:

ab = (ab)

Now, you can use the difference of cubes formula:

(a^3 - b^3) = (a - b)(a^2 + ab + b^2)

Plug in the values:

(a^3 - b^3) = [(3a - 7b)/3][(a^2 + ab + b^2)]

Now, divide the entire expression by b^3:

[(a^3 - b^3) / b^3] = [(3a - 7b)/3][(a^2 + ab + b^2)] / b^3

Simplify further if needed, but this is the expression for (a^3 - b^3) / b^3 given a/b = 7/3.

User JJohnson
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