Question

There resistors 2 Ω , 6 Ω and 9 Ω are connected in parallel. Calculate the equivalent resistance A. 2.3Ω B. 1.3 Ω C. 1.0 Ω D. 17.0 Ω​

Answer 1

The correct answer is B. 1.3 Ω.

Step-by-step explanation:

To calculate the equivalent resistance of resistors connected in parallel, you can use the formula:

1 / Req = 1 / R1 + 1 / R2 + 1 / R3

Where:

Req is the equivalent resistance

R1, R2, R3 are the resistances of the individual resistors

In your case, R1 = 2 Ω, R2 = 6 Ω, and R3 = 9 Ω. Plug these values into the formula:

1 / Req = 1 / 2 Ω + 1 / 6 Ω + 1 / 9 Ω

Now, calculate the inverses:

1 / Req = (1/2 + 1/6 + 1/9)

To add these fractions, find a common denominator, which is 18:

1 / Req = (9/18 + 3/18 + 2/18)

Now, add the fractions:

1 / Req = (14/18)

Now, take the reciprocal of both sides to find Req:

Req = 18 / 14

Simplify the fraction:

Req = 9 / 7 ≈ 1.2857 Ω

Rounded to one decimal place, the equivalent resistance is approximately 1.3 Ω.

So, the correct answer is B. 1.3 Ω.