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A wooden block of mass 400 grams floats vertically in a liquid of density 0.8 grams/cm^3. If the volume of the block is 625 cm^3, what is the volume of the block above the surface of the liquid?

User Xion
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Answer:

625 cm^3

Step-by-step explanation:

The weight of the wooden block is given by the equation:

Weight of block = density of liquid × volume of block × g

where g is the acceleration due to gravity (approximately 9.8 m/s²).

The buoyant force on the block when it is floating is equal to the weight of the block. So the buoyant force can be expressed as:

Buoyant force = density of liquid × volume above liquid × g

Since the block is floating, the weight of the block and the buoyant force are equal:

Weight of block = Buoyant force

Substituting in the given values:

density of liquid × volume of block × g = density of liquid × volume above liquid × g

Canceling out the g terms:

density of liquid × volume of block = density of liquid × volume above liquid

Dividing both sides of the equation by the density of the liquid:

volume of block = volume above liquid

Given that the volume of the block is 625 cm³, the volume above the liquid is also 625 cm³.

User Chemark
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