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For points (-1,-5) and (2,2), what is the slope-intercept form and standard form? Slope-intercept form: y = (7/3)x - 4 Standard form: 7x - 3y = -12

User Xgdgsc
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Final answer:

The slope-intercept form of the equation is y = (7/3)x - 4. The standard form of the equation is 7x - 3y = -12.

Step-by-step explanation:

To find the slope-intercept form and standard form for the given points, we need to first find the slope between the two points. The formula for slope is given by:

slope (m) = (y2 - y1) / (x2 - x1)

Using the values from the given points, we have:

slope (m) = (2 - (-5)) / (2 - (-1)) = 7/3

To find the slope-intercept form, we can substitute the slope value and one of the point's coordinates into the equation y = mx + b. Using the point (-1, -5), we have:

y = (7/3)x + b

Substituting the x and y values and solving for b, we get:

-5 = (7/3)(-1) + b

Simplifying the equation, we get:

b = -4

Therefore, the slope-intercept form of the equation is:

y = (7/3)x - 4

To find the standard form of the equation, we can rearrange the slope-intercept form equation:

y = (7/3)x - 4

3y = 7x - 12

7x - 3y = -12

Learn more about Slope-Intercept Form

User Daralthus
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