194k views
0 votes
For points (-1,-5) and (2,2), what is the slope-intercept form and standard form? Slope-intercept form: y = (7/3)x - 4 Standard form: 7x - 3y = -12

User Xgdgsc
by
8.9k points

1 Answer

5 votes

Final answer:

The slope-intercept form of the equation is y = (7/3)x - 4. The standard form of the equation is 7x - 3y = -12.

Step-by-step explanation:

To find the slope-intercept form and standard form for the given points, we need to first find the slope between the two points. The formula for slope is given by:

slope (m) = (y2 - y1) / (x2 - x1)

Using the values from the given points, we have:

slope (m) = (2 - (-5)) / (2 - (-1)) = 7/3

To find the slope-intercept form, we can substitute the slope value and one of the point's coordinates into the equation y = mx + b. Using the point (-1, -5), we have:

y = (7/3)x + b

Substituting the x and y values and solving for b, we get:

-5 = (7/3)(-1) + b

Simplifying the equation, we get:

b = -4

Therefore, the slope-intercept form of the equation is:

y = (7/3)x - 4

To find the standard form of the equation, we can rearrange the slope-intercept form equation:

y = (7/3)x - 4

3y = 7x - 12

7x - 3y = -12

Learn more about Slope-Intercept Form

User Daralthus
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories