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Solve the following simultaneous equations 4m + 3n = 18; 3m - 2n = 5 ​

User Jon Reilly
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Answer:

m = 3 , n = 2

Explanation:

given the equations

4m + 3n = 18 → (1)

3m - 2n = 5 → (2)

multiplying (1) by 2 and (2) by 3 and adding the result will eliminate n

8m + 6n = 36 → (3)

9m - 6n = 15 → (4)

add (3) and (4) term by term on both sides to eliminate n

(8m + 9m ) + (6n - 6n) = 36 + 15

17m + 0 = 51

17m = 51 ( divide both sides by 17 )

m = 3

substitute m = 3 into either of the 2 original equations and solve for n

substituting into (1)

4(3) + 3n = 18

12 + 3n = 18 ( subtract 12 from both sides )

3n = 6 ( divide both sides by 3 )

n = 2

solution to the simultaneous equations is m = 3 , n = 2

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