Question

A line joins the points A(-2, -5) and B(4, 13). Find the equation of the perpendicular bisector of AB. a. x - 2y = -1 b. x + 2y = 1 c. x - 2y = 2 d. x + 2y = -2

Answer 1

Hi,

Explanation:

A=(-2,-5)

B=(4,13)

Middle of [AB]=M=(1,4)

slope of AB=(13+5)/(4+2)=18/6=3

Slope of the perpendicular bisector= -1/3

Equation of the perpendicular bisector:

y-4=(x-1)*(-1/3)

3y-12=-x+1

x+3y=13