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Three positive integers greater than 1 have a product of 27000 and are pairwise relatively prime. What is their sum?
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Three positive integers greater than 1 have a product of 27000 and are pairwise relatively prime. What is their sum?

User Sriram
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7 votes

Answer:

Hi,

Explanation:


27000=27*1000=3^3*10^3=3^3*2^3*5^3\\\\The \ three\ numbers\ are\ 3^3=27, 2^3=8, 5^3=125\\\\Their\ sum \ is\ 27+8+125=\boxed{160}\\

User Shernett
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