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Solve the following system of equations: x=50+3y 5x−10y=500 a) (48, 5) b) (50, 0) c) (71, 7) d) (80, 10)

User Bates
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1 Answer

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Answer: x = 200, y = 50

Explanation:

Since one of our equations in our system is directly equal to one of the variables we are looking for, x, we can substitute that equation into x in the equation 5x - 10y = 500 to solve for y first:

5(50 + 3y) - 10y = 500
250 + 15y - 10y = 500
250 + 5y = 500
-250 -250
5y = 250
/ 5 / 5
y = 50

Now that we know the value of y, we can plug the value of y into the equation x = 50 + 3y (you can also plug it into the other equation, but this equation will be a bit easier since it's directly solving for x):

x = 50 + 3(50)
x = 50 + 150
x = 200

We can check our values by plugging both into 5x - 10y = 500:

5(200) - 10(50) = 500
1000 - 500 = 500
500 = 500

Both sides are equal to each other, so we correctly computed the values of x and y; x = 200 and y = 50.

I hope this helps! :)

User Paulo Matos
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