Question

The activation energy for the gas phase decomposition of dinitrogen pentoxide is 103 kJ. N₂O₅=2 NO₂ + 1/2 O₂ The rate constant at 305 K . The rate constant will be 0.00110 at_________ K.

Answer 1

The activation energy for the gas phase decomposition of dinitrogen pentoxide is given. We can calculate the temperature at which the rate constant is 0.00110 using the Arrhenius equation.

Step-by-step explanation:

The activation energy for the gas phase decomposition of dinitrogen pentoxide is 103 kJ. The reaction can be represented as:

N2O5 → 2NO2 + 1/2O2

To find the temperature at which the rate constant is 0.00110, we can use the Arrhenius equation:

k = Ae-Ea/RT

where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin. Rearranging the equation, we have:

T = Ea / (ln(k/A))

Plugging in the given values of Ea = 103 kJ and k = 0.00110, we can calculate the temperature T.

T = 103 kJ / (ln(0.00110/A))

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Answer 2

The activation energy is 103 kJ for the gas phase decomposition of dinitrogen pentoxide. To find the temperature at which the rate constant is 0.00110, use the Arrhenius equation: k = A * e^(-Ea/RT). Plug in the values and solve for the temperature.

Step-by-step explanation:

The activation energy is the minimum amount of energy required for a chemical reaction to occur. In the gas phase decomposition of dinitrogen pentoxide, the activation energy is 103 kJ. The reaction produces 2 molecules of nitrogen dioxide (NO₂) and half a molecule of oxygen (O₂). The rate constant is a measure of how fast the reaction occurs.

To find the temperature at which the rate constant is 0.00110, we can use the Arrhenius equation:

k = A * e^(-Ea/RT)

Where:

k is the rate constant

A is the pre-exponential factor

Ea is the activation energy

R is the ideal gas constant

T is the temperature in Kelvin

Given the rate constant (k) at 305 K is 0.00110, we can plug in the values into the equation and solve for the temperature:

0.00110 = A * e^(-103/(8.314 * 305))

From here, we can solve for A:

A = 0.00110 / e^(-103/(8.314 * 305))

Once we have the value of A, we can substitute it back into the original equation and solve for the temperature at which the rate constant is 0.00110.

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