Question

Marita claims

that the sum of three consecutive counting numbers is three times the second number. prove that this conjecture is true

Answer 1

True

Explanation:

let x = the first counting number

x + 1 = 2nd

x + 2 = 3rd

x + x + 1 + x + 2 = 3x + 3

the sum of three consecutive counting numbers is three times the second number

3x+3 = 3(x+1)

3x + 3 = 3x + 3

Answer 2

let x be the 1st number, (x+1) the 2nd consecutive, (x+2) the 3rd consecutive

sum :

x+x+1+x+2 = 3x+3

3x+3= 3(x+1)

→the sum of three consecutive counting numbers is three times the second numbe

Explanation: