Question

A particle moves at a speed of 3.7 m/s in the +x direction. Upon reaching the origin, the particle receives a continuous constant acceleration of 0.67 m/s2 in the -y direction. A. What is the position of the particle 3.9 s later?

Answer 1

First get final velocity:

3.7 + -.67(3.9) = 1.087 m/s

Then use kinematics to find distance:

9.335 m