Answer:
To determine the energy dissipated when a charge moves through a potential difference, you can use the formula for electric potential energy:
\[U = q \cdot V\]
Where:
- \(U\) is the electric potential energy in joules (J).
- \(q\) is the charge in coulombs (C).
- \(V\) is the potential difference in volts (V).
In your case, you have a charge of 20 coulombs (\(q = 20 \, \text{C}\)) and a potential difference of \(0.5 \times 10^2 \, \text{mV}\), which can be written as \(0.5 \times 10^{-2} \, \text{V}\) (\(V = 0.5 \times 10^{-2} \, \text{V}\)).
Now, you can calculate the energy dissipated:
\[U = q \cdot V = 20 \, \text{C} \cdot 0.5 \times 10^{-2} \, \text{V} = 10^{-1} \, \text{J}\]
So, the energy dissipated is \(0.1 \, \text{J}\).