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What distance in travel corresponds to 5 ?sec of time for electromagnetic energy?

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Final answer:

The distance corresponding to 5 seconds of time for electromagnetic energy is approximately 1.5 x 10^9 meters.

Step-by-step explanation:

The distance traveled by electromagnetic energy can be calculated using the equation v = d/t, where v is the speed of light, d is the distance traveled, and t is the time. The speed of light is approximately 3 x 10^8 m/s. To find the distance corresponding to 5 seconds of time, we can rearrange the equation to solve for d: d = v * t. Substituting in the values, we get d = (3 x 10^8 m/s) * 5 s = 1.5 x 10^9 meters.

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