Question

1. Find an equation of the line L that passes through the point (-3, 9) and satisfies the given condition. (Let x be the independent variable and y be the dependent variable.) L is a horizontal line. 2. Find an equation of the line L that passes through the point (-1,8) and satisfies the given condition. (Let x be the independent variable and y be the dependent variable.) The x-intercept of L is 4 3. Find the slope and y-intercept of the line with the equation 4x-5y+8 (Last post didnt help, please proofread and make sure because I am more confused than i was before now. Thank you for all your help!!

Answer 1

To find the equation of a horizontal line, set the slope to zero. To find the equation of a line with a given x-intercept, set the y-coordinate of the x-intercept to 0. The given equation can be rewritten in slope-intercept form to find the slope and y-intercept.

Step-by-step explanation:

To find the equation of a horizontal line, we know that the slope of the line is zero. Therefore, the equation of the line L passing through the point (-3, 9) is y = 9.

To find the equation of a line with a given x-intercept, we know that the y-coordinate of the x-intercept is 0. Therefore, the equation of the line L passing through the point (-1, 8) with an x-intercept of 4 is y = -2x + 6.

The given equation 4x - 5y + 8 = 0 can be rewritten in slope-intercept form as y = 4/5x + 8/5. Therefore, the slope of the line is 4/5 and the y-intercept is 8/5.

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