Question

`Let's just consider the concept of stoichiometry without any confusing chemicals. Here is a generic equation: 2Q + 3R → 3S + 4T. If you mix 5 units of Q and 7 units of R, what would be the limiting reactant?

Answer 1

Step-by-step explanation:

To determine the limiting reactant, we need to compare the number of moles of each reactant to the stoichiometric ratio in the balanced equation.

In the given equation 2Q + 3R → 3S + 4T, the stoichiometric ratio tells us that for every 2 moles of Q, we need 3 moles of R. So, let's calculate the number of moles of Q and R based on the units you provided.

For Q: 5 units of Q

For R: 7 units of R

Now, let's assume that each unit of Q and R is equivalent to 1 mole. Therefore, we have:

Number of moles of Q = 5 moles Number of moles of R = 7 moles

Next, we compare the ratio of moles of Q and R to the stoichiometric ratio of Q and R in the equation. We have:

Q:R ratio = 5 moles : 7 moles Q:R stoichiometric ratio = 2 moles : 3 moles

This tells us that the ratio of Q to R is less than the stoichiometric ratio. Therefore, Q is the limiting reactant because we do not have enough Q to completely react with the available R.

I hope that answers your question!