Question

(2x^2-3x+1) + (4x^2-2x-5)

Answer 1

To solve this, we need to keep in mind the Order of Operations - or PEMDAS.

First, working left to right, we solve what is within the parenthesis first.

Meaning that the first thing we need to evaluate is (2x^2 - 3x + 1).

`(2x^2-3+1) = ?`

The step that comes after Parenthesis is Exponents.

`2x^2 = 4x`

Next we subtract 3x from 4x.

`4x-3x=1x`

Because we cannot combine unlike terms, we can't add 1 to 1x. So now our equation looks like this:

`(1x+1) + (4x^2-2x-5)`

Now we need to evaluate what's inside the next set of Parenthesis.

`(4x^2-2x-5)`

Exponents come first, so we solve 4x^2 before anything else in this set of parentheses.

`4x^2=16x`

Now we subtract 2x from 16x.

`16x-2x=14x`

Again, because of the inability to combine unlike terms, we cannot subtract 5 from 14x.

Our final equation is this -

`(1x+1)+(14x-5)`

I hope this helps you!