Question

Match the terms in the left column to the appropriate blanks in the sentences on the right. Not all terms will be used. Reset Help 9:3:3:1 The law of states that genes have alternative forms, or alleles. In a mitosis organism, the two alleles of a gene separate during and gamete formation; each dihybrids sperm or egg carries only one allele of each pair. This law explains the ratio of the F2 phenotypes observed when self-pollinate. Each organism inherits one allele for diploid each gene from each parent. In individuals, the two alleles are different, and independent assortment expression of the allele masks the phenotypic effect of the allele. In monohybrids individuals, the two alleles are identical. segregation The law of states that the pair of alleles for a given gene segregates into gametes 3:1 independently of the pair of alleles for any other gene. This law explains the ratio of meiosis the F2 phenotypes in a cross between heterozygous homozygous dominant recessive Part A In human blood types, Rh positive is a trait that shows simple dominance over Rh negative. The Rh phenotype is recorded by stating "positive" or "negative" after the individuals ABO blood type. A woman who has blood type A positive has a daughter who is type o positive and a son who is type B negative. Which of the following phenotypes is possible for the father? A negative O negative AB negative B positive Submit Request Answer Part A Having polydactyly (extra digits on hands and feet) is a dominant trait. A man has polydactyly. His wife and oldest daughter do not have polydactyly. The couple's second child has polydactyly. What is the probability that their next (third) child will have extra digits? 1/8 3/4 1/2 1/16 Submit Request Answer Part A In a particular plant, green seed color is dominant to blue. If two plants with green seeds were crossed and resulted in 302 green and 98 blue seed plants, what was the most probable genotype of each parent? gg x Gg GXG o Gg x Gg GG ~ Gg

Answer 1

The father's possible blood types include B positive, AB negative, B negative or AB positive. The chance the couple's next child will have polydactyly is 1/2. The parent plants' most probable genotype would be Gg x Gg.

Step-by-step explanation:

The question revolves around Mendelian inheritance, specifically concepts of dominant and recessive traits, probability and alleles. For the first question, let's analyze the blood types. The children's blood types suggest the father could not be any type O, as the son has type B blood. So, the possible blood type for the father could be B positive, AB negative, B negative or AB positive. For the second question, if the father is polydactyl and the mother is not, they're obviously heterozygous. The possibility that their next child will have polydactyly is 1/2, as the child could inherit the dominant allele from the father and the recessive from the mother. Lastly, the most probable genotype of the parent plants with green seeds that produced offspring with some blue seeds would be Gg x Gg as blue seeds are recessive and would only manifest if inherited from both parents.

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