Final answer:
The slope of the line when graphing ln(N) versus t is 0.00910.
Step-by-step explanation:
To find the slope of the graph of ln(N) versus t, we need to differentiate the given function. The derivative of ln(N) with respect to t can be found using the chain rule. Differentiating the function N=0.892e^(0.00910t) gives us dN/dt = 0.00910 * 0.892e^(0.00910t).
Next, we need to find the derivative of ln(N). Using the chain rule, we have d(ln(N))/dt = (1/N) * (dN/dt). Substituting the derivative we found earlier, we get d(ln(N))/dt = (0.00910 * 0.892e^(0.00910t)) / (0.892e^(0.00910t)). Simplifying further, we have d(ln(N))/dt = 0.00910.
Therefore, the slope of the line when graphing ln(N) versus t is 0.00910.
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