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How many electrons must be removed from a neutral object to leave a net charge of Q2 = 1.7 μC?

User Chansen
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Final answer:

To leave a net charge of Q2 = 1.7 μC, we need to remove 1.0625 x 10^13 electrons from a neutral object.

Step-by-step explanation:

In order to determine the number of electrons that must be removed from a neutral object to leave a net charge of Q2 = 1.7 μC, we need to use the formula:

Q = Ne

where Q is the net charge in coulombs, N is the number of electrons, and e is the elementary charge (1.6 x 10-19 C).

Substituting the given value of Q2 = 1.7 μC into the equation, we have:

1.7 x 10-6 C = N x 1.6 x 10-19 C

Solving for N, we get:

N = 1.7 x 10-6 C / (1.6 x 10-19 C)

N = 1.0625 x 1013 electrons

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User Kunal Pareek
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