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3x−8y+44=0 7x=12y−56

User Jack
by
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1 Answer

5 votes

Answer:

(4, 7 )

Explanation:

given the 2 equations

3x - 8y + 44 = 0 → (1)

7x = 12y - 56 ( subtract 12y - 56 from bpth sides )

7x - 12y + 56 = 0 → (2)

multiplying (1) by 7 and (2) by - 3 and adding the result will eliminate x

21x - 56y + 308 = 0 → (3)

-21x + 36y - 168 = 0 → (4)

add (3) and (4) term by term to eliminate x

(21x - 21x) + (- 56y + 36y) + (308 - 168) = 0

0 - 20y + 140 = 0 ( subtract 140 from both sides )

- 20y = - 140 ( divide both sides by - 20 )

y = 7

substitute y = 7 into either of the 2 orinal equations and solve for x

substituting into (1)

3x - 8(7) + 44 = 0

3x - 56 + 44 = 0

3x - 12 = 0 ( add 12 to both sides )

3x = 12 ( divide both sides by 3 )

x = 4

solution is (4, 7 )

User Manna
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