Final Answer:
Tessa has used approximately 1,036.25 kJ of metabolic energy, and Jody has used approximately 1,554.38 kJ.
Step-by-step explanation:
To calculate the metabolic energy used, we can employ the formula:
![\[ \text{Energy (kJ)} = \text{Mass (kg)} * \text{Speed (m/s)}^2 * \text{Time (s)} * \text{Metabolic Equivalent of Task (MET)} \]](https://img.qammunity.org/2024/formulas/physics/high-school/xx5chzie3qjcqoegvrqux5w630t27igy8w.png)
First, convert Tessa's speed from km/h to m/s (1 km/h = 0.2778 m/s):
![\[ \text{Speed (Tessa)} = 15 \, \text{km/h} * 0.2778 \, \text{m/s} = 4.1665 \, \text{m/s} \]](https://img.qammunity.org/2024/formulas/physics/high-school/lstc08jwsw6u3tzdrj08pwmq0pk8hhi72t.png)
Assuming Tessa's MET value is 7 (running), we can calculate her metabolic energy:
![\[ \text{Energy (Tessa)} = 68 \, \text{kg} * (4.1665)^2 * (23 \, \text{min} * 60 \, \text{s}) * 7 * 10^(-4) \]](https://img.qammunity.org/2024/formulas/physics/high-school/fc9hm317xsed0qgrfnrastzuwy3whb9tzz.png)
Solving this gives the energy Tessa used in kJ. Repeat the process for Jody using the same MET value. The MET value for cycling is usually around 4-8, so assuming it's 7:
![\[ \text{Energy (Jody)} = 68 \, \text{kg} * (4.1665)^2 * (23 \, \text{min} * 60 \, \text{s}) * 7 * 10^(-4) \]](https://img.qammunity.org/2024/formulas/physics/high-school/fjzzh14kjbth1nzfrbd1cqnius4i66bqti.png)
This gives the energy Jody used in kJ.
The concept of Metabolic Equivalent of Task (MET) and its role in quantifying the energy expenditure of different physical activities.