148k views
4 votes
Use polar coordinates to find the volume of the solid below the paraboloid z=72−2x ^2 −2y ^2 and above the xy-plane.

User David Wolf
by
8.4k points

1 Answer

2 votes

Final answer:

To find the volume of the solid below the paraboloid z = 72 - 2x^2 - 2y^2 and above the xy-plane using polar coordinates, set up a triple integral and carry out the integration to calculate the volume.

Step-by-step explanation:

To find the volume of the solid below the paraboloid z = 72 - 2x^2 - 2y^2 and above the xy-plane using polar coordinates, we can set up a triple integral.

First, we need to express the equation of the paraboloid in terms of polar coordinates. We know that x = r cos(theta) and y = r sin(theta). Substituting these values into the equation, we get z = 72 - 2(r cos(theta))^2 - 2(r sin(theta))^2.

The bounds of integration for the triple integral are:
- r ranges from 0 to √(36/2) (since the paraboloid is symmetric, we only need to consider the positive hemisphere)
- theta ranges from 0 to 2π (full revolution around the z-axis)

The volume is given by the triple integral:
Volume = ∫∫∫ r dz dr dtheta. By carrying out the integration, the volume can be calculated.

User Eja
by
7.5k points

Related questions

asked Feb 1, 2024 135k views
Tipsy asked Feb 1, 2024
by Tipsy
7.5k points
1 answer
2 votes
135k views
asked Jan 13, 2024 125k views
Jason Jin asked Jan 13, 2024
by Jason Jin
7.8k points
1 answer
0 votes
125k views
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories