Question

FB​=Fgaity ​{rhoHg​(1−x)+rhowater ​x}Vg ​=rhosteel ​Vg rhoHgg​​(1−x)+rhowater ​x=rhosteel ​​ Rearrange above equation for fraction of ball bearing volume above mercury surface x=rhoHg​−rhowater ​rhoHg​−rhosteel ​​

Answer 1

The equation x = H−water/H−steel is rearranged to solve for the fraction of the ball bearing volume above the mercury surface.

Step-by-step explanation:

The equation given, x = ρHg - ρwater / (ρHg - ρsteel), is rearranged to solve for the fraction of the ball bearing volume above the mercury surface. This equation relates the densities of different substances and the volume of the ball bearing. By rearranging the equation, we can easily calculate the value of x using the known values of ρHg, ρwater, and ρsteel.

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