Final answer:
To give a coin a positive charge of +1.1x10^-7 coulombs, roughly 6.875 x 10^11 electrons would need to be removed. The calculation is based on the elementary charge, which is the charge of a single electron.
Step-by-step explanation:
The student is asking about how many electrons would need to be removed from a coin to give it a positive charge of +1.1×10^−7 coulombs. To answer this, you need to understand that each electron carries a charge of -1.6×10^-19 coulombs. This value is known as the elementary charge, and it's the smallest charge that can exist freely in nature. To leave a coin with a positive charge of +1.1×10^−7 coulombs, we would need to divide that charge by the charge of a single electron:
+1.1×10^−7 C / -1.6×10^−19 C/e = -(1.1/1.6)×10^12 electrons
This indicates that roughly 6.875 × 10^11 electrons would need to be removed. The negative sign just shows that electrons, which are negatively charged, are being removed to leave a positive charge.
Learn more about Charge of an Electron