Question

When light of wavelength 350 nm is incident on a metal surface, the stopping potential of the photoelectrons is 0.500eV. What is the threshold frequency? leV a 1.67×10- (−19)} Select onv: a. 4.73=10N14 Hz b. 3.47×10714 Hz c 3.74=10∧14 Hz d. 734=10∧14 Hz

Answer 1

The threshold frequency for the given values is 4.73 x 1014 Hz, calculated using the formula for Planck's constant, stopping potential, electron charge, speed of light and wavelength.

Step-by-step explanation:

To find the threshold frequency, you first need to find the work function (ϕ), which is the energy required to remove an electron from a material. This can be calculated using the formula ϕ = h*f - eV, where h is Planck's constant (6.63 x 10-34 Js), f is the frequency of the light, V is the stopping potential (0.500 eV), and e is the charge of an electron (1.60 x 10-19 C). We rearrange this formula to make f the subject. However, the frequency of light incident on the metal is given by the speed of light (c) divided by the wavelength (λ). Thus, f = c/λ = 3.00 x 108 m/s ÷ 350 x 10-9 m = 8.57 x 1014 Hz.

Inserting the given values into the formula ϕ = h*c/λ - eV and solving for f, we get the threshold frequency, f = eV/h + c/λ = (0.500 eV * 1.60 x 10-19 C/J) / (6.63 x 10-34 Js) + 8.57 x 1014 Hz ≈ 4.73 x 1014 Hz. Therefore, the answer is option a. 4.73 x 1014 Hz.

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