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If a pot of water at room temperature (20 ^∘C) takes 4.0 minutes to boil, how long will it take for all the water to evaporate? Specific Heat of water =4186 J/(kg.C) Latent Heat of Evaporation of water =2.26×10^6 J/kg

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Final answer:

To calculate the time taken for water to evaporate, we need to determine the energy required to heat the water to its boiling point and then the energy required to convert it from a liquid to a gas. The time can be determined by dividing the total energy by the power of the stove. However, without the power of the stove, an exact time cannot be provided.

Step-by-step explanation:

The time it takes for water to evaporate can be calculated by determining the energy required to heat the water to its boiling point and then the energy required to convert it from a liquid to a gas. First, we calculate the energy required to heat the water to its boiling point using the specific heat capacity of water. Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. The mass can be determined based on the density of water, which is 1000 kg/m³. With this information, we can calculate the energy required to heat the water to its boiling point. Q = (1000 kg/m³) * (4186 J/(kg*C)) * (100 °C - 20 °C). Next, we calculate the energy required to convert the water from a liquid to a gas using the latent heat of evaporation. Q = mL, where Q is the energy, m is the mass, and L is the latent heat of evaporation. With the mass from the previous calculation, we can calculate the energy required to evaporate the water. Q = (1000 kg/m³) * (2.26 * 10^6 J/kg). Finally, we can add the two energies together to find the total energy required to evaporate the water. With this information, we can determine the time it takes for the water to evaporate by dividing the total energy by the power of the stove. However, without the power of the stove, we cannot provide an exact time.

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