Final answer:
To solve the function f(x) = 2^(3x+1) - 6 using the switch and solve method, set f(x) equal to zero, add 6 to both sides, take the logarithm (base 2) of both sides, isolate the variable x, and solve for x by dividing both sides by 3.
Step-by-step explanation:
To solve the function f(x) = 2(3x+1) - 6, you can use the switch and solve method. Here's how you can solve it step-by-step:
- Start with the equation f(x) = 2(3x+1) - 6.
- Set f(x) equal to zero and solve for x.
- 2(3x+1) - 6 = 0.
- Add 6 to both sides of the equation to get 2(3x+1) = 6.
- Take the logarithm (base 2) of both sides to undo the exponentiated term. This gives you 3x+1 = log2(6).
- Subtract 1 from both sides to isolate the variable. This gives you 3x = log2(6) - 1.
- Finally, divide both sides by 3 to solve for x. This gives you x = (log2(6) - 1) / 3.
So, the solution to the function f(x) = 2(3x+1) - 6 is x = (log2(6) - 1) / 3.
Learn more about Solving exponential equations