Final answer:
To obtain the balanced chemical equation for the given cell notation, separate half-reactions for the anode (oxidation) and cathode (reduction) are written and combined while ensuring electron and charge balance.
Step-by-step explanation:
The student is asking to write a balanced chemical equation from provided cell notation. This notation corresponds to an electrochemical cell setup, and we need to write separate half-reactions for the cathode and the anode and then combine them to get the overall balanced chemical equation.
The cell notation given is: Fe(s) | Fe²+(aq) || NO₃⁻(aq) | NO(g) | Pt(s)
For the oxidation half-reaction at the anode we have:
Fe(s) → Fe²+(aq) + 2e⁻
And for the reduction half-reaction at the cathode we would have something like:
NO₃⁻(aq) + 3e⁻ + 4H+(aq) → NO(g) + 2H₂O(l)
Note that the reduction half-reaction may vary based on the complete cell reaction. Now we combine these half-reactions ensuring the electrons are balanced:
Fe(s) + 4HNO₃(aq) → Fe(NO₃)₃(aq) + NO(g) + 2H₂O(l)
The reaction must also be charge-balanced and may require additional balancing of the HNO₃ and water molecules.