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The voltage across a load is v(t)=10 42 cos(ωt+10 ∘ )V, and the current through the load is i(t)=28 2cos(ωt−40 ∘ )A. The reference direction for the current points into the positive reference for the voltage.

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5 votes

Answer:

your question is wrong

Step-by-step explanation:

please right correct question

User Adrian Grigore
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