Question

What's the equation of the parabola that has its vertex at (4,–1) and a y-intercept at (0,7)? Question 2 options: A) y = –1∕2(x + 4)² – 1 B) y = 1∕2(x + 4)2²– 1 C) y = 1∕2(x – 4)² – 1 D) y = 1∕2(x – 4)² + 1

Answer 1

Hi

Answer: C

Explanation:

`y=k*(x-4)^2-1\\if\ x=0\ then\ y=7 = > 7=k*(-4)^2-1 = > 7=k*16-1 = > 16k=8 = > k=1/2\\\\\boxed{y=(1)/(2) *(x-4)^2-1}`