71.6k views
0 votes
The graph of 3x + 4y = - 12 does not pass through thequadrant. (a) First (b) second (c) third (d) fourth

User Kotoj
by
7.7k points

1 Answer

6 votes

Answer: First

Step-by-step explanation

Plug in x = 0 to solve for y.

3x + 4y = -12

3(0) + 4y = -12

4y = -12

y = -12/4

y = -3

The y intercept is located at (0,-3). This point is on the negative y axis which is the boundary between quadrants 3 and 4. If a non-vertical line passes through such a point, then this line must pass through quadrants 3 and 4.

Plug in y = 0 to solve for x.

3x + 4y = -12

3x + 4(0) = -12

3x = -12

x = -12/3

x = -4

The x intercept is (-4,0) which is on the boundary between quadrants 2 and 3.

Therefore, the line 3x+4y = -12 passes through quadrants 2, 3, and 4.

Quadrant 1 is the only quadrant that the line 3x+4y = -12 does not pass through. The graph below confirms this.

The graph of 3x + 4y = - 12 does not pass through thequadrant. (a) First (b) second-example-1
User Cdesmetz
by
8.0k points

Related questions

1 answer
1 vote
18.1k views
1 answer
5 votes
93.9k views