Question

Let P(x,y) denote the point where the terminal side of an angle θ meets the unit circle. If P is in Quadrant IV and x=1/3 , find tan(θ) .

Answer 1

Explanation:

y is negative being in quadrant IV

`y=-\sqrt{1^2-((1)/(3) )^2} =-\sqrt{(8)/(9) } =-(2√(2) )/(3) \\tan \theta=(y)/(x) =((-2√(2) )/(3) )/((1)/(3) ) =-2√(2) \approx-70.5^\circ\\\approx ~360-70.5\\\approx 289.5^\circ`