Question

"A thermometer attached to an airplane flying at 36000 ft reads -400F. What is the corresponding temperature at sea level below if the average lapse rate is 3.60F/1000 ft."

Answer 1

Based on the given information and the average lapse rate of 3.6°F/1000 ft, is approximately -169.6°F.

Step-by-step explanation:

To find the corresponding temperature at sea level based on the given information, we can use the lapse rate to calculate the temperature decrease with altitude. Here's how to calculate it step-by-step:

Given:

Temperature at 36,000 ft = -40°F

Lapse rate = 3.6°F/1000 ft

Step 1:

Calculate the temperature difference between 36,000 ft and sea level.

The altitude difference between 36,000 ft and sea level is 36,000 ft. Using the lapse rate of 3.6°F/1000 ft, we can find the temperature difference: Temperature difference = 3.6°F/1000 ft * 36,000 ft

Step 2: Subtract the temperature difference from the temperature at 36,000 ft to find the corresponding temperature at sea level. Temperature at sea level = Temperature at 36,000 ft - Temperature difference

Substituting the given values:

Temperature at sea level = -40°F - (3.6°F/1000 ft * 36,000 ft)

Now, let's calculate the temperature at sea level:

Temperature at sea level = -40°F - (3.6°F/1000 ft * 36,000 ft)

Temperature at sea level = -40°F - 129.6°F

Temperature at sea level = -169.6°F

Therefore, the corresponding temperature at sea level, based on the given information and the average lapse rate of 3.6°F/1000 ft, is approximately -169.6°F.