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Suppose that 3 books are picked at random from a shelf containing 4 novels, 6 books of poe and a dictionary. (a) Find the probability that the dictionary is selected. (b) Find the probability that 2 novels and 1 book of poems are selected Suppose that 3 books are picked at random from a shelf containing 4 novels, 6 books of poems, and a dictionary. (a) Find the probability that the dictionary is selected. (b) Find the probability that 2 novels and 1 book of poems are selected

User Webmonkey
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Answer:

See below

Explanation:

On the shelf we have 4 novels, 6 books of poetry, and 1 dictionary.

The total number of books on the shelf are 4+6+1 = 11 books

a) to find the probably of the dictionary being selected, we observe how many dictionaries are there over the total amount of books. that gives us the probability that the dictionary is selected.

Since there is 1 dictionary out of 11 books, the probability is 1/11

b) to find the probability that 2 novels AND 1 book of poems is selected we calculate the probabilities for each case separately and then multiply them. The answers can differ based on whether or not the question wants you to assume that the books are placed back after picking or not returned to the shelf. I will calculate for both cases since it's not specified in this question.

For returning the books back to the shelf after picking:

P(2 novels) = P(1 novel) * P(1 novel) = 4/11 * 4/11 = 16/121

P(1 book of poems) = 6/11

P(2 Novels and 1 book of poems) = P(2 novels) * (P 1 book of poems) = 16/121 * 6/11 = 96/1331

For not returning the books back to the shelf after picking it out:

P(2 novels) = P(1 novel) * P(1 novel) = 4/11 * 3/10 = 12/110 = 6/55

P(1 book of poems) = 6/9 = 2/3

P(2 Novels and 1 book of poems) = P(2 novels) * (P 1 book of poems) = 6/55 * 2/3 = 12/165 = 4/55

I hope this helps :)

User LuckyLuke
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