Question

Pure gold has a density of 19.32 g/cm³ how large would a pieace of hold be if it had a mass of 318.97g?

Answer 1

16.51 cm³

Step-by-step explanation:

Density

We can use the following formula to calculate density:

`D=(m)/(V)` where D is density, m is mass and V is volume

We're given:

• D = 19.32 g/cm³
• m = 318.97 g
• V = ?

Isolate V in the equation:

`D=(m)/(V)\\\\V=(m)/(D)`

Solve for V:

`V=(318.97)/(19.32)`

`V = 16.5098343685`

Round to significant figures;

`V = 16.51\hspace{4}cm^3`