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Calculate the heat lost in joules by 115 g of water as it cools from 71.4 Celsius to 34.4 Celsius

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Answer:To calculate the heat lost by 115 grams of water as it cools from 71.4°C to 34.4°C, you can use the formula for heat transfer:

Q = m * C * ΔT

Where:

Q = Heat lost (in joules)

m = Mass of the substance (in grams)

C = Specific heat capacity of water (4.18 J/g°C)

ΔT = Change in temperature (in Celsius)

First, calculate the change in temperature:

ΔT = Final temperature - Initial temperature

ΔT = 34.4°C - 71.4°C = -37°C

Now, plug the values into the formula:

Q = 115 g * 4.18 J/g°C * (-37°C)

Q = 115 g * 4.18 J/g°C * (-37)

Q ≈ -18,965.9 Joules

Explanation: Since the water is cooling down, the heat is being lost, so the heat lost is approximately -18,965.9 Joules. However, it's important to note that conventionally, heat lost is considered as a positive value, so you can express it as approximately 18,965.9 Joules.

User Yugantar Kumar
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