Answer:
28 g of CaO
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated:
CaCO₃ —> CaO + CO₂
Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:
Molar mass of CaCO₃ = 40 + 12 + (16×3)
= 40 + 12 + 48
= 100 g/mol
Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g
Molar mass of CaO = 40 + 16
= 56 g/mol
Mass of CaO from the balanced equation = 1 × 56 = 56 g
SUMMARY:
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
Finally, we shall determine the mass of CaO that will be obtained by the decomposition of 50 g of CaCO₃. This can be obtained as follow:
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
Therefore, 50 g of CaCO₃ will decompose to produce = (50 × 56)/100 = 28 g of CaO.
Thus, 28 g of CaO were obtained from the reaction.