Answer:
To find the number of 5-digit numbers greater than 43,000 that can be formed using the digits {2, 3, 4, 5, 6, 7} with repetition allowed, we can break it down into the following cases:
1. For the first digit (the thousands place), it can be 4, 5, 6, or 7 (since it must be greater than 4).
2. For the remaining four digits (the units, hundreds, tens, and ones places), each can be any of the digits {2, 3, 4, 5, 6, 7}.
Now, we can calculate the number of possibilities for each case:
1. For the first digit, there are 4 choices (4, 5, 6, or 7).
2. For the remaining four digits, each has 6 choices (2, 3, 4, 5, 6, or 7), as repetition is allowed.
So, the total number of 5-digit numbers greater than 43,000 that can be formed is:
4 (choices for the first digit) * 6^4 (choices for the remaining four digits) = 4 * 6^4
Now, calculate this value:
4 * 6^4 = 4 * 1,296 = 5,184
So, the correct answer is A. 8×6⁴, which is 4 * 6^4.
Explanation: