Question

Skateboarder with a mass of 45 kg is riding on a skateboard with a mass of 2.5 kg what should be the velocity of the skateboarder if she hast to attain a momentum of 264 kg meters per second?

Answer 1

To find the velocity of the skateboarder, use the equation for momentum and plug in the given values: 264 = (45 + 2.5) x velocity of skateboarder. The velocity of the skateboarder should be approximately 5.84 m/s.

Step-by-step explanation:

To calculate the velocity of the skateboarder, we can use the equation for momentum: momentum = mass x velocity. The skateboarder's momentum is given as 264 kg m/s, and their mass is 45 kg. The mass of the skateboard is 2.5 kg. So, to find the velocity of the skateboarder, we use the equation: momentum of skateboarder = (mass of skateboarder + mass of skateboard) x velocity of skateboarder.

Plugging in the given values, we have: 264 = (45 + 2.5) x velocity of skateboarder. Solving for velocity of skateboarder, we find that it should be approximately 5.84 m/s.

Answer 2

To solve this problem, we can use the principle of conservation of momentum. The momentum of an object is given by the equation p = mv, where p is the momentum, m is the mass, and v is the velocity. In this case, the skateboarder and the skateboard are initially at rest, so their combined momentum is 0. After the skateboarder starts moving, she will have a momentum of 264 kg m/s. The velocity of the skateboarder should be approximately 5.55 m/s.

Step-by-step explanation:

To solve this problem, we can use the principle of conservation of momentum. The momentum of an object is given by the equation p = mv, where p is the momentum, m is the mass, and v is the velocity. In this case, the skateboarder and the skateboard are initially at rest, so their combined momentum is 0. After the skateboarder starts moving, she will have a momentum of 264 kg m/s. Let's denote the velocity of the skateboarder as v. The mass of the skateboarder is 45 kg and the mass of the skateboard is 2.5 kg.

According to the principle of conservation of momentum, the momentum before the skateboarder starts moving is equal to the momentum after she starts moving. So we have:

0 = (45 kg + 2.5 kg) × v

Simplifying the equation, we get:

47.5 kg × v = 264 kg m/s

Dividing both sides of the equation by 47.5 kg, we get:

v = 264 kg m/s / 47.5 kg

v ≈ 5.55 m/s

Therefore, the velocity of the skateboarder should be approximately 5.55 m/s.