Question

Wgat is the value of 2(x^(2)+3yz)-:(x+z) when x=2 y=3 and z=5

Answer 1

By substituting the values of variables into the equation and using the order of operations, the final result of the provided equation will be 91.

Step-by-step explanation:

In order to determine the value of the given equation 2(x^2+3yz)-(x+z) when x=2, y=3, and z=5, you have to substitute these values into each corresponding variable in the equation.

1. Substitute 2 for x, 3 for y, and 5 for z in the equation: 2((2^2)+3*3*5)-(2+5).
2. Calculate the equation inside the parentheses first according to the order of operations (PEMDAS/BODMAS): {2[(4)+45]-(7)}.
3. Carry out the operations inside the square brackets first: {2[49]-7}.
4. Then, proceed with other math operations: {98-7}.
5. Finally, you got 91 as the result.

Learn more about Value of the equation