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Rationalise the denominator by 6 root 7 minus 1

Rationalise the denominator by 6 root 7 minus 1
52.7k views
18 votes
Rationalise the denominator by 6 root 7 minus 1

User Zac Charles
by
8.2k points

1 Answer

10 votes

Answer:

Assuming the numerator was 1.


(6√(7)+1)/251

Explanation:

Assuming the numerator was 1.


1/(6√(7) -1)\\ (6√(7)+1)/((6√(7) - 1)(6√(7) + 1))\\ (6√(7)+1)/((6√(7))^2 + 6√(7) - 7√(7) - 1)\\(6√(7)+1)/((6√(7))^2 - 1)\\(6√(7)+1)/((36*7 - 1)\\(6√(7)+1)/251

User Ben Stock
by
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